
First of all, we try to find out the summation series of the series.
Then, we use the Integral Test here which is:
If \(\int_0^\infty f(x) \, dx\) convergent, then \(\sum_{n=0}^{\infty} a_n\) is convergent.
If \(\int_0^\infty f(x) \, dx\) convergent, then \(\sum_{n=0}^{\infty} a_n\) is divergent.
Then you basically take the \(\lim_{m \to \infty} \int_0^m f(x) \, dx\) which in this case is \(\frac{1}{3+4x}\).
You proceed to take the integral with U-Substitution and then finally taking the limit.
Since the limit does not equal to 0, it diverges which is the final answer.
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